A while ago I recevied a newsletter rom Physics Forums and was telling somebody about the format but could not locate the newsletter in my inbox. I was wondering if anybody has a newsletter sent from PF that they might send to me? The newsletter informed of new posts, active discussions, minthly...
A centrifuge is a device in which a small container of material is rotated at a high speed on a circular path. Such a device is used in medical laboratories, for instance, to cause the more dense red blood cells to settle through the less dense blood serum and collect at the bottom of the...
Ok, so after looking at this problem a bit differently, it is obvious that what the question is asking for is the max height of the projectile, right? In that case then the equation would be:
V^2=V{o}^2-2gy
V{o}=6.93 m/s
V=0 m/s
g=9.80 m/s^2
y=?
I guess then my question becomes a...
I wanted to try this question using this LATEX code, so here it is:
My Variables
V{0} = 6.93 m/s
V = 0 m/s
a = 9.80 m/s^2
My Equation
V^2=V{o}^2+2aY
My Work
V^2=V{o}^2+2aY --> Y=V^2 - V{o}^2/2a --> Y=(0^2 - 6.93^2)/(2)(9.80) --> 2.45m
LATEX is really cool! It will surely take...
Answer Verification...*Please*
Hi Everybody,
I am having a problem with a homework question and think that I have finally got it right this time! Can somebody verify my work on this problem and let me know if I did indeed do this problem correctly? If not then can anybody help point me in...
Ah-HA! Now I get it. It's like the light just went off after reading all of these replies. Now it makes total sense.
Thank you all for your help! I look forward to posting again and eventually being able to help others as well.
- Doug
Yeah - what must come up MUST of course come down :) I get the difference between velocit and acceleration now.
So then to solve the problem at hand, I figure I need to use the laws of kinematics...
If so, the I set the variables up like so:
x = ? (NEED TO SOLVE FOR)
a = -9.80 ,/s^2...
Thank you all for your replies!
Here is the complete question
"A projectile is fired horizontally with an initial speed of 50.0 m/s. Neglect air resistance. What is the magnitude of the acceleration of the projectile 3.00 s after it is fired?"
Doc Al, wouldn't the acceleration of a...
A projectile is fired with an initial speed of 50.0 m/s. Neglect air
resistance. What is the magnitude of the acceleration of the projectile
3.00 sec after it is fired?
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I am using the following equation...