Recent content by Dramen

Yep I checked it and the numbers work. Thanks for the nudges in the right direction.

ok I did that so that 2(3s-s^2)-1=s+1 setting it to 0 gives me -2s^2+5s-2=0 and solving for that I get s=1/2 and s=2 then I plug those answers into t=3s-s^2 so that t=1.25 and t=2 so then my points of intersection are at P (1.25,1.5) and (2,3) Q (1.25,1.5) and (2,3)

I'm no good when trying to solve for 2 unknowns algebraically like this, because first thought is to substitute t=3s-s^2 into 2t-1=s+1 but that won't work. And by graph for the first equation t=s=0 or 2 and the second t=s=2

I did just that quite a while ago when my instructor had hinted at that idea and this is what I came up with t=3s-s^2 t=s(3-s) so that for x t=s and t=3-s so that any same two values fit in the first equality(?) and only 1.5 solves the equality in the second for y it is 2t-1=s+1 2t=s+2 so that...

Homework Statement I'm told to find the 2 points the two curves P and Q will intersect on and the parametric equations are: P (x=t, y=2t-1) Q (x=3t-t^2, y=t+1) The Attempt at a Solution I know I'm supposed to set x-equations and y-equations equal to each and solve so that...

Yeah somehow my brain started to die out on me when doing my sign change test. So would the correct order of sign change be: - 1 + 2 + 3 - 4 - 5 + (+'s and -'s are the sign in between the intervals) so that the local extrema are: 1, 3, 5 with points 2 and 4 where the f(x) just goes flat...

yeah I already got to that part. so that simplified it is: f"(x) = (\frac {1}{x-1}+\frac{2}{x-2}+\frac{3}{x-3}+\frac{4}{x-4}+\frac{5}{x-5})((x-1)(x-2)^2(x-3)^3(x-4)^4(x-5)^5) thing is now how would I find out what kind of extrema the roots of f'(x)/critical points of f(x) with such a long...

Yeah my teacher wanted me to avoid using the product rule and chain rule combo to differentiate it, which was your first example. Though your second example with the logarithmic differentiation is the one I needed for my problem thanks for reminding me and the help.

Yeah sorry I need second derivative because the main question asked for the critical points for f(x) (not known) which I already know are 1, 2, 3, 4, 5, but it also asked what kind of extrema the points are and to prove which extrema they are and I need the second derivative to prove it.

Need help differentiating multiple quantities Homework Statement f′(x) = (x − 1)(x − 2)^2(x − 3)^3(x − 4)^4(x − 5)^5 I need help in trying to differentiate this equation. I know could use a combination of the chain and product rule to figure it out, but my teacher said that doing so would...

Okay I finally got it thanks for all the help, however my answer differs from yours in that mine is: f^{-1}(x)=\ln \frac {-x}{x-1} Thing is though when I run mine through the checks it still works, but when I used yours I just get errors.

Yeah I have no idea why I have it either only put it there because dextercioby had one. Also if your talking about the e^y+1 then its alright because somehow I fudged typing the equation right and accidentally turned it from an addition sign to a subtraction one.

@dextercioby okay I was able to get my answer though I would like to know if the steps I made to recreate your answer are right x=\frac{e^y}{e^y+1} multiply the denominator on both sides to get xe^y+x=e^y multiply both sides by -1? -e^y+xe^y=-x factor out the ey to then get e^y(x-1)=-x divide...

I must be an idiot or still suffering from my high school senioritis because even with all your help (which is very appreciated). I still can't get a decent answer as my calculator gets me error values, low decimals (to check against f(x)), or the numbers are negative. @SammyS this is what I...

I see the mathematical errors now because when I was first typing it on my home computer the connection was bad and had problems typing it out and previewing it before posting. However, it seems that even with your assistance I'm still having problems with finding the inverse function as my...