Thank you HallsofIvy,
How about if I restate the problem as:
\int_0^\infty e^{-\Sigma_t s}f(s)ds=\int_0^\infty e^{-\Sigma_t s}g(s)ds
And it should hold for any \Sigma_t \in [0,\infty)
for very large \Sigma_t\to\infty, the only contribution is just right from zero and because the...
I have the following problem.
If
\int_0^\infty f(s)ds=\int_0^\infty g(s)ds
What are sufficient conditions such that f(s)=g(s)?
I know that two functions f(s),g(s) are equal if their domain, call it S, is equal and if f(s)=g(s) for all s\in S but I can't figure this one out.
The full...