Thanks for that. I am sure you are right about SI units. My goal was just to see if I could get a hard number for mps or fps or rpm that resulted from the energy input to the vertical rotation. Assuming 180 rpm of original speed . (I added downstroke to imply vertical rotation). My degree is in...
Thanks for the reply... I guess I am not good at stating the problem, sorry for the lack of Engineering savvy...Assume for illustrative purposes that 20 pounds was added to the downstroke for a distance of one foot and was removed immediately after that one foot of distance. What I am...
I am an independent inventor. This is not homework. I already have a degree, it is just not in Engineering. The force I am adding is rotational force or torque. This is a device I am building and I am looking to optimize the design. Ideally I would like to know the "payoff" for the input of...
If there was a free-spinning effective weight of 20 lbs. at a 20" radius rotating at 180 rpm (15.7 fps?) and a force of 20 foot pounds was added, what would be the increase in velocity/speed? (Ignoring friction and wind losses).
An enclosed cylindrical* (disc) vessel one inch thick and five inches in radius holding two pounds of fluid at ambient atmospheric pressure (14psi?)and being spun at 30,000 rpm's. Assume the centrifugal force acting on the fluid creates a pressure of 1,000 psi. The question is ...
"If the...
Here are two equations showing a nearly equivelant energy output for a given volume and velocity of water. Using the formula:
EKin = M/2 x Vsquared
250/2 x 15.34m/s x 15.34m/s = 29,414 KW (requires 5 times more volume)
50/2 x 35m/s x 35m/s...