Recent content by DrJekyll

I'm no good with Green's functions, hence the post. However I did come up with a solution: First, I know the solution to (\partial_x^2 - K^2)G(x,x') = F(x) is -\int dx' F(x') \frac{e^{-K |x-x'|}}{2 K} So we just need to look for the function that produces -1/2K times the...

I am trying to find the solution to a problem defined as follows: (\partial_x^2-K^2)^2 G(\vec{x},\vec{x}')=\delta(\vec{x}'-\vec{x}) where K is simply a constant and x is three dimensional. A \left[ e^{-K(\vec{x}-\vec{x}')}H(\vec{x}-\vec{x}') + e^{K(\vec{x}-\vec{x}')}H(\vec{x}'-\vec{x})...

Ok, so resurrecting this thread since I'm back to trying to solve using Matab. Here are the equations I'm trying to solve again, with the last one being a constraint equation. So far I've been using a 4rth order Runge-Kutta scheme to solve the first 6 equations with some initial conditions...

I've just recently tried this as well. One difference though, \frac{\partial^2 Q}{\partial x^2} - K^2 Q = \frac{4 \partial u_y}{3 \partial x} + \frac{4 i \omega u_x}{9} (without actually checking, they look mostly the same, the above is definitely the correct one, any differences would...

My notation may be a bit confusing. b_x represents the x component of b not the partial derivative. Also b=b(x,t), the y and z directions can be safely ignored.

I've got a set of coupled Ingegro-Differential equations that I've been working on for a while. Here they are: \frac{\partial b_x}{\partial t} = i x b_x + i u_x \frac{\partial b_y}{\partial t} = i x b_y + i u_y \frac{\partial b_z}{\partial t} = i x b_z + i u_z - \frac{3}{2 \omega} b_x...