Recent content by drofenaz

I was mixing up my p-test for 0->∞ and 0->1.

So it's because of the limits that it is convergent. If it were from 1 to 0 it would be divergent?

I'm not sure I quite understand. When the comparison equation is near 0, the graph is up at +∞. So how is it possible that it is convergent?

Homework Statement Use the Comparison Theorem to determine whether the integral is convergent or divergent. \int_{0}^{1}\frac{e^{-x}}{\sqrt{x}} Homework Equations The Attempt at a Solution \int_{0}^{1}\frac{e^{-x}}{\sqrt{x}} \leq \int_{0}^{1}\frac{1}{x^{\frac{1}{2}}} Because p<1, the...

I have solved the problem. Hopefully typing up my work will help someone someday.SOLVING FOR KNOWNS i_r=cos\theta+sin\theta \frac{di_r}{dt}=-sin\theta+cos\theta \frac{di_r}{dt}=\frac{d\theta}{dt}i_\theta i_\theta=-sin\theta+cos\theta \frac{di_\theta}{dt}=-cos\theta-sin\theta...

So basically I'm doing it completely wrong. Would my work be correct for v and a instead of ω and \alpha? I'm not quite sure how to solve the problem. Could you point me in the right direction?

Homework Statement Derive the expressions for the i_r and i_θ components of velocity and acceleration. Homework Equations r=|r|i_r \omega=\frac{dr}{dt} \alpha=\frac{dω}{dt}=\frac{d^2r}{dt} The Attempt at a Solution r=|r|i_r \omega=\frac{dr}{dt}i_r+r\frac{di_r}{dt}...