Recent content by dswatson
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How Do These Brain Teasers Challenge Your Mind?
1.being at the end of your rope 2. 3. the "I" of the hurricane 4. splitting hairs 5.- dswatson
- Post #3
- Forum: General Discussion
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Ranking capacitors by the potential difference across them.
I have a circuit that is in a read only file so I can't get an image on here so I will try to create it on here B-battery C-capacitor ----C1------------- l.....l...l B...C2...C3 l.....l...l -------------------- Ignore the periods (.) because they are just place holders. The...- dswatson
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- Capacitors Difference Potential Potential difference Ranking
- Replies: 1
- Forum: Introductory Physics Homework Help
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Gaussian surfaces can someone help walk me through this problem?
Gaussian surfaces...need help...can someone help walk me through this problem?? A solid insulating sphere of radius 5 cm carries a net positive charge of 2 μC, uniformly distributed throughout its volume. Concentric with this sphere is a conducting spherical shell with inner radius 10 cm and...- dswatson
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- Gaussian Surfaces
- Replies: 1
- Forum: Introductory Physics Homework Help
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Where Can the Electric Field Be Zero Between Point Charges?
ok just drawing a picture with the arrowed lines was a huge help thank you- dswatson
- Post #3
- Forum: Introductory Physics Homework Help
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Where Can the Electric Field Be Zero Between Point Charges?
A charge 2q and a charge -q sit a distance of d away from one another. In what region of space can the electric be zero? The answer has to be answered conceptually and not mathematically. Pictures would be helpful. I understand how to do the problem mathematically and that at some point between...- dswatson
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- Field Physics
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
awesome! thank you so much for all of the help I really appreciate it...- dswatson
- Post #17
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
so my final answer so far is... r(s)=<5sin(s/5),4cos(s/5),3cos(s/5)> so are my new parameters...0<s/5>2*pi so...0<s<10*pi- dswatson
- Post #15
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
well nevermind that doesn't work because there are no "s"'s in the eqn- dswatson
- Post #14
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
0<s<10*pi ?- dswatson
- Post #13
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
is this simply s(t)=5t plugged back into the original r(t)?- dswatson
- Post #11
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
my problem is that i don't what you mean to solve for t...my equation for arc length was 5t evaluated over 0<t<2*pi. To solve for t, what is 5t equal to? this is where I'm completely confused...- dswatson
- Post #10
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
ok...so assuming that is is correct...where do I begin on the next step? I am a little behind in calc and am trying to catch up... I now have to "reparameterize this curve with respect to arc length (find "r(s)"). Don't forget to specify the range for the arc length parameter...- dswatson
- Post #8
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
ok nevermind i see where i messed up...i shouldn't have made the cos a sin. If i leave it as it was before... int[sqrt{25cos^2(t)+16sin^2(t)+9sin^2(t)}dt] then just combine the sin terms i get int[sqrt{25cos^2(t)+25sin^2(t)}dt] this gives me... int[sqrt{25} equals... int[5]...- dswatson
- Post #6
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
I feel like I did do all of the derivatives... I did x'=5cost, y'=-4sint, and z'=-3sint then square them... x'^2=25cos^2(t), y'^2=16sin^2(t), and z'^2=9sin^2(t) the add them but convert x'^2 to a factor of sin^2(t) first. 25cos^2(t)=25(1+sin^2(t)) then distribute and I ended up...- dswatson
- Post #5
- Forum: Calculus and Beyond Homework Help
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Calculating Arc Length of a Curve: Caculus III Formula and Reparameterization
ok so i have gotten this far. int[sqrt{(25+sin^2(t))}] where do I go from here? It doesn't factor or that would make it easy.- dswatson
- Post #3
- Forum: Calculus and Beyond Homework Help