A particle P travels with constant speed in a circle of radius 7.4 m and completes one revolution in 22.0 s (see Figure). The particle passes through O at t = 0 s. What is the magnitude of the average velocity during the interval from t = 4.4 s and t = 18.7 s.
I used T=2(pi)r / v
22 =...
oh, sorry.
took R = v0^2 * sin2(theta) /2g
turned it into v0^2 * 2 * sin(theta) * cos(theta) / 2g (trig identity)
crossed out the 2s
plugged in 28 for theta, 42.6 for v0, and 2.45 (.25*9.8) for G. - solved.
got 307.042 meters - got the question wrong...
i guess it doesn't...
19.[2pt]
On a distant planet, golf is just as popular as it is on earth. A golfer tees off and drives the ball 4.00 times as far as he would have on earth, given the same initial velocities on both planets. The ball is launched at a speed of 42.6m/s at an angle of 28.2o above the horizontal...