I used the kinematic equations...Final Velocity Squared=Distance x acceleration (.31 x 9.8 =V) then multiplied that b/c it was the change in V times the mass...got impulse
triangle wave and the point is between 1-3 on top of the 2 in the X...ive tried that but it doesn't give me the answer.
i can find initial momentum but how do i find speed at 4 seconds?
On the Y there are 3 tick marks in this order top to bottom 2 0 -2.
On the X there are the numbers 1-4 (time in seconds).
From 0-1 in the X it follows the 0 on the Y, from 2-3 there is an impulse that goes up to the 2 (Coordinate 2,2) in the Y then from 3-4 it remains on 0 force. Probably...
Momentum/Impulse Graph...Finding Velocity
A 0.125 kg ball, moving in the positive direction at 12 m/s, is acted on by the impulse shown in the graph in Figure 9-16 What is the ball's speed at 4.0 s?
If the picture doesn't load as an attachment I'll have to try it again.
Okay so I'm not...