Recent content by duke1

that didnt do it

I've worked out and finished this one now.

I've worked out and finished this one now.

I've worked out and finished this one now.

I've worked out and finished this one now.

I used the kinematic equations...Final Velocity Squared=Distance x acceleration (.31 x 9.8 =V) then multiplied that b/c it was the change in V times the mass...got impulse

triangle wave and the point is between 1-3 on top of the 2 in the X...ive tried that but it doesn't give me the answer. i can find initial momentum but how do i find speed at 4 seconds?

Does anyone know how to get the image approved?

On the Y there are 3 tick marks in this order top to bottom 2 0 -2. On the X there are the numbers 1-4 (time in seconds). From 0-1 in the X it follows the 0 on the Y, from 2-3 there is an impulse that goes up to the 2 (Coordinate 2,2) in the Y then from 3-4 it remains on 0 force. Probably...

Nope there is Force in the Y and Time in the X

It says they are pending approval.

Can someone point me in the right direction?

Momentum/Impulse Graph...Finding Velocity A 0.125 kg ball, moving in the positive direction at 12 m/s, is acted on by the impulse shown in the graph in Figure 9-16 What is the ball's speed at 4.0 s? If the picture doesn't load as an attachment I'll have to try it again. Okay so I'm not...

ok thanks a lot...the hint really helped so i picked out one of the kinematics we got in class...thx for the help

ok...so 9.8 is free fall but how can i use that without another time or something? I am sure I am missing something simple