Recent content by dukkie

thanks! I got it!

d=F/k correct? so that would mean d=(M1+M2)(g)(mew)/(k) right?

ohhhhhhh...so F=ma so F= (mew)(g)(M1+M2) right?

a=(M1+M2)(g)(mew)/(M1)? I confused myself again... ps-i will be back at noon est.

a=(M1)(g)(mew)/(M1) so a=(g)(mew)

so (a=F/m), correct?

0.3(M1)(g)=0.3(0.49 kg)(9.81 m/s^2)

I am really sorry. I know that I am probably missing the most simple solution, and I am truly not trying to get you to do the problem for me, but I honestly don't know what to do. I don't have either force or acceleration and need them. I am confused and on top of it have been told that this...

But friction force is the coefficient of friction multiplied by the normal force, and I can't figure out the normal force because I don't know the acceleration. I am very confused.

Is the max. force exerted on the second block by the first block (0.49 kg)(9.81 m/s^2)? Which would make the max. acceleration (9.81 m/s^2) right?

Ok, I'm stuck again... A block of mass M1=0.490 kg sits on a block with a mass of M2=4.50 kg that rests on a frictionless surface and is connected to a spring. The spring has a spring constant of k=16.6 N/m. The block is displaced and undergoes Simple Harmonic Motion. What is the largest...

thanks. that was my problem. my calculator was set on degrees instead of radians.:blushing: ooops!

Here is what I was given in the problem: A 0.27 kg mass is suspended on a spring that stretches a distance of 4.9 cm. It is then pulled downward an addtional distance of 12.5 cm and released. Find the displacement from the equilibrium position of the mass (in cm) after 0.42 sec. Count up...

Thanks so much for your help. I miss the most simple solutions sometimes. It helped a lot for you to explain it. Thanks again. I got it right.:smile:

A block of mass 0.25 kg is connected to a spring with a spring constant (k) of 35 N/m. It is oscillating on a frictionless horizontal surface. It's speed as it passes through equilibrium is 1.04 m/s. What is the total energy of the system? I know that E=0.5(k)(A)^2. I just can't figure out...