Recent content by dvaughn

Homework Statement Find points on curve y=sinhx where the tangent line has slope 2 Homework Equations The Attempt at a Solution y' = 1/(sqrt(1-x^2)) = 2 4 = 1/(1-x^2) 4-4x^2=1 x=sqrt(3/4) the actual answer should be x = +or- ln(2+sqrt(3))

Find the equation of the tangent line to the curve y=(lnx)^cosx at the point (pi/2, 1)? The Attempt at a Solution lny = cosx(ln(ln(x))) d/dx = -sinx(ln(ln(x))) + cosx/(ln(x)(x)) y' = y(-sinx(ln(ln(x))) + cosx/(ln(x)(x))) this is the part where I get stuck