Homework Statement
Find points on curve y=sinhx where the tangent line has slope 2
Homework Equations
The Attempt at a Solution
y' = 1/(sqrt(1-x^2)) = 2
4 = 1/(1-x^2)
4-4x^2=1
x=sqrt(3/4)
the actual answer should be x = +or- ln(2+sqrt(3))
Find the equation of the tangent line to the curve y=(lnx)^cosx at the point (pi/2, 1)?
The Attempt at a Solution
lny = cosx(ln(ln(x))) d/dx
= -sinx(ln(ln(x))) + cosx/(ln(x)(x))
y' = y(-sinx(ln(ln(x))) + cosx/(ln(x)(x)))
this is the part where I get stuck