Find points on curve with a tangent line

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SUMMARY

The discussion focuses on finding points on the curve defined by the function y = sinh(x) where the tangent line has a slope of 2. The derivative of the function, y' = cosh(x), is set equal to 2, leading to the equation 4 - 4x^2 = 1. The correct solutions for x are x = ±ln(2 + √3), derived from the hyperbolic sine function and its properties. Key derivatives and identities, such as the derivative of arcsin(x), are also referenced in the solution process.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically sinh(x) and cosh(x)
  • Knowledge of derivatives and their applications in finding slopes of tangent lines
  • Familiarity with logarithmic functions and their properties
  • Basic calculus concepts, including implicit differentiation and solving equations
NEXT STEPS
  • Study the properties and applications of hyperbolic functions, particularly sinh and cosh
  • Learn how to derive and apply the chain rule in calculus
  • Explore logarithmic identities and their role in solving equations
  • Investigate the relationship between derivatives and tangent lines in various functions
USEFUL FOR

Students studying calculus, particularly those focusing on derivatives and tangent lines, as well as educators seeking to explain hyperbolic functions and their applications.

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Homework Statement


Find points on curve y=sinhx where the tangent line has slope 2



Homework Equations





The Attempt at a Solution


y' = 1/(sqrt(1-x^2)) = 2
4 = 1/(1-x^2)
4-4x^2=1
x=sqrt(3/4)

the actual answer should be x = +or- ln(2+sqrt(3))
 
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d/dx(sinhx)=coshx = (ex+e-x)/2

then solve for ex
 
Remember that the derivative of arcsin x or sin-1x = 1/√(1 - x2). sinh is the hyperbolic sine.
 

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