I guess it would be (σ^2)/10 and (σ^2)/20, so it's (σ^2)/n and (σ^2)/2n for \bar{X}_1 and \bar{X}_2, respectively.
I subbed that into
\text{Var}(a \bar{X}_1 + b \bar{X}_2) = a^2 \text{Var}(\bar{X}_1) + b^2 \text{Var}(\bar{X}_2)
and subbed in a and b, and I got
(σ^2(w^2+1))/2n
I still...