Recent content by dynoma5

ahh i see if you put it that way then i can see what you mean. Again thanks for the clarification!

omg i see it now. Even the question was implying that the m1 was going to go backward after collision but I was thinking that m1 was suppose to go forward too after the collision so I thought I did something wrong. kk so for c1 i got -3.33 m/s and c2 i got 6.67 m/s. using conservation of energy...

kk so then i'd get m1(v1 - c1) = m2(v1 +c1) m1v1 - m2v1 = m2c1 + m1 c1 so c1= (m1v1 - m2v1)/(m2+m1) but that would give me a negative which means that m1 would travel back after collision?

Homework Statement A block of mass m1 = 5.00 kg is released from A. It makes a head on elastic collision at B with a block of mass m2=10.0kg that is initially at rest. Calculate the maximum height to which m1 rises after the collision Homework Equations Pi = Pf Ef= Ei + other work...