Recent content by E=m(C)^2

Oh ok, thanks a lot guys.

Hey guys, I'm trying to propose an appropriate resistance based sensors to measure the deflection of a beam and the strain of the metal on the underside of the beam for an old peer with steel beams which are somewhat corroded. The system has to measure the strength of these beams. I'm trying to...

Too true tony, i forgot to breakdown the u=44.3 into a horizontal component. Once broken down it should equal 31.32m/s and this correct value for u leads to t=6.38m/s. Sorry guys

Basically for question 1 you need to have separate the information into a vertical component and a horizontal component. Vertical: u=?, v=0, a=-9.8 and x=100, as you calculated. From here use equation v^2=(u^2)+2as, where u=initial velocity and s=displacement. From this you schould get...

Oops sorry your acceleration value is correct, my mistake. Everything else should be ok, sorry.

Newton's Second Law is F=ma, hence a=m/F, giving a value of 0.81m/s squared in this case. Now you can use v=u+at for part a) where u=27m/s, a=0.81 and t=7.5. For part b) you could use the formula s=ut+0.5a(t^2). Hope that helps.

OK, the general formula for the volume of a sphere is V=(4/3)pi(r^3), where r=radius and pi=3.14 approx. Question 1 you just have to simply substitute r=5 into the equation. For Question 2 you find the volume of the Earth plus the atmosphere together, having a radius of 6500km, and subtract from...

Alright for question 2 in the first scenario the particle is traveling east and it's velocity is increasing as acceleration is positive. In the second the particle is once more traveling east but it's velocity is decreasing as acceleration is negative. In the third it is traveling east with...

Oh ofcourse, seems so simple now. Thanks a lot guys.

Hi guys, I'm having a little trouble finding the equation of the tangent to the curve 2e^(xy) - ysinx = log(y) + 2 at the point (0,1). I've basically concluded that either the equation should be used or either find the gradient at (0,1) through differentiation and then use (y-y1)=m(x-x1)...

one thing to think about, if the positive direction is upwards, how could the ball travel up when it has a negative initial velocity?

You seem to have used the formula y=ut+0.5a(t^2), transposed it and obtained u=(y/t)-0.5at, so as long as you have your positive and negative directions right you've done it right, i think.

Thanks a lot guys, i really appreciate it. Sorry about the double post Hootenanny and believe me i made some effort but yeah didn't really show it, sorry about that. Won't happen again. Thank you again.

Help! Hi everyone, This is my very first post on physics forum! I was wondering if anyone could help explain to me how to find the coordinates of a point where a line intersects a plane. The question I'm trying to do has given the line as r= (2, 7, -5) + t(1, 2, -1) and the...