Recent content by e4physics

Hi, I have the same question. If the offer still valid as i can not see any banner

Thanks for your quick reply

Hi is the educator.com offer still valid

Hi I am trying to solve this question in my book but i am not getting the write answer , can some one explain this. Question : The approximate force which would tend to impact the proximal fragment on the nail and distal fragment in the diagram above is ---------- NEWTONS? I tried to...

the weight of the y component acts down on him and the y component of T acts upwards so ∑ Y forces = 588.6N - 49.05N = 539.55 normal force will be equal in magnitude t the y foces μ = 84.95 N / 539.55N = 0.1574 HAVE I UNDERSTOOD IT CORRECT LY??

Solution for friction equilibrium THANKS FOR GUIDING ME - I NEED FURTHER HELP I have solved this according to your advice. Confusion i have about angle. i did 90-60=30 x Component of T = 98.1* COS 30° = 84.95N y component of T = 98.1 SIN 30° = 49.05 SUM X forces is only 84.95N...

The person in the system above has a mass of 60 kg. If the system is in equilibrium, what is the coefficient of friction between the person and the ground, to two decimal places? I need help on this question , I have done some work on it which is given below: Converted masses into...