Hi I am trying to solve this question in my book but i am not getting the write answer , can some one explain this.
Question : The approximate force which would tend to impact the proximal fragment on the nail and distal fragment in the diagram above is ---------- NEWTONS?
I tried to...
the weight of the y component acts down on him and the y component of T acts upwards
so ∑ Y forces = 588.6N - 49.05N = 539.55
normal force will be equal in magnitude t the y foces
μ = 84.95 N / 539.55N = 0.1574
HAVE I UNDERSTOOD IT CORRECT LY??
Solution for friction equilibrium
THANKS FOR GUIDING ME - I NEED FURTHER HELP
I have solved this according to your advice. Confusion i have about angle. i did 90-60=30
x Component of T = 98.1* COS 30° = 84.95N
y component of T = 98.1 SIN 30° = 49.05
SUM X forces is only 84.95N...
The person in the system above has a mass of 60 kg. If the system is in equilibrium, what is the coefficient of friction between the person and the ground, to two decimal places?
I need help on this question , I have done some work on it which is given below:
Converted masses into...