Hi SammyS,
I got the - \frac{2\, \sin\!\left(\frac{3\, n\, \mathrm{pi}}{2}\right)}{\left(n^2 - 1\right)} from simplifying the previous part of the expression \frac{\sin\!\left(\frac{3\, n\, \mathrm{pi}}{2}\right)}{\left(n + 1\right)} - \frac{\sin\!\left(\frac{3\, n\...