Recent content by Ebo

  1. E

    Calculating g using horizontal uniform circular motion

    After another look at my data I realize I was wrong. M(2) was in fact smaller than M(1), not bigger. I somehow forgot that. Which means that the formula works. I don't get the correct value, but my teacher told me I probably wouldn't, so that's okay. Thank you so much! This has really helped...
  2. E

    Calculating g using horizontal uniform circular motion

    Alright ... T(2)^2 = M(2)^2 * ((4*π^2*R)/T^2)^2 + M(2)^2 * g^2 T(1)^2 = M(1)^2 * g^2 Solving for g ... g^2*(M(2) - M(1))^2 = M(2)^2 * ((4*π^2*R)/T^2) g = (4*π^2*R*M(1))/((T^2)*(M(1)-M(2)) The trouble is, this gives me a negative value for g (because M(1)<M(2)).
  3. E

    Calculating g using horizontal uniform circular motion

    The vertical component equals M2*g, and the horizontal component equals the centripedal force. If I add them together (as vectors), I would get the tension in the string connected to the rotating mass and the tension in this string equals the tension in the hanging mass (=M1*g) However, if I...
  4. E

    Calculating g using horizontal uniform circular motion

    I have drawn (several) free body diagrams, but they don't seem to help me much. I really don't see how I can calculate T2 without knowing θ. I tried to use this formula: g = (4*π^2*R*M2)/(T^2*(M2-M1) However, this gave me a value of nearly 20 m s^-2, so I guess it's wrong(?) I’m not...
  5. E

    Calculating g using horizontal uniform circular motion

    Hi! I’ve recently done an experiment that I didn’t completely understand and now it seems I’ve lost all my notes as well (the notes written down from the teacher’s board, with a formula I really need, but didn’t understand). This work is supposed to be completed during the summer holiday, so I...
Back
Top