Yes I've also heard this. However, the University of Illinois has a pretty nasty reputation for not giving much, if any, aid.
Thanks for the reply,
It's funny you should mention working. I'm currently working full-time and going to school full-time at my local community college. It's pretty...
Hello all, I'll start with some background info on myself.
I'm a middle class white male who has the 'honor' of calling Cornfield, Illinois home. Due to personal choice, and financial restrictions, (okay mostly financial restrictions) I've been attending a local community college and...
I have 'The Elegant Universe' by Brian Greene. I'd rate it as mediocre, there are some interesting aspects to it (the history of M theory for example) and some negative (terrible god forsaken examples). I would not recommend you spend your hard earned, or freely given, currency on it.
I think I'm finally seeing the light, when finding the gravitational force I need to use sin(10°), and when finding the the kinetic friction force, I need to use cos(10°), as kinetic friction uses a ratio of the normal force, which is in the Z direction.
I'm not quite sure how to account for...
Haha yeah you did stump me for a while there, thanks for all the help you've given so far, I appreciate it.
So, recapping I have these forces acting on the block in the X direction:
Force of gravity: .1kg * 9.8m/s2*cos(10°) = .965N -X
Force of Kinetic Friction: .250*M*G*cos(10°) = .241N...
Well, I didn't know for sure, but I assumed that because I wanted the total force of gravity to be on the hypotenuse of the right triangle used to find the x and z components of gravity, I adjusted the triangle's position accordingly. And now that I'm taking a second look at my work this morning...
I know that kinetic friction depends on the Normal force of the object, and that in this case the normal force would only be a ratio of the total amount of gravitational force [MGcos(10°)*coefficient of friction]...you got me, I think just found my logical error. So the total amount of force...
Ah, so the .241N is the total force of gravity + kinetic friction opposing the motion of the block?
I had forgotten about Hooke's law, let's see if I have it right:
FSpring= kx so,
F = 400N/m * .1m = 40N
Thanks for the quick reply.
Hey all, here's a question from one of my homework sets, any help is greatly appreciated.Homework Statement
I've included a diagram of the situation. Basically, I have to find out how long it takes the block to reach the end of the ramp, the spring is massless, and friction is a factor in this...
Hey all, here is a simple problem provided as a review for our final by my professor. I think I have everything right, but if history offers any insight into the future, I'm dead wrong.
Any help is greatly appreciated.Homework Statement
A 30kg box sits on a 10kg wagon. the wagon is pulled by...
Homework Statement
A pole P (300kg, length = 12m) is sliding on a frictionless surface at 8.28m/s. The pole's velocity is perpendicular to the poles length. A mass N (.5kg) collides with one end of the pole at 1043m/s and sticks.
How fast does the pole rotate after the collision?
Homework...