Recent content by Echoeric666

Sorry, I meant 45 meters up as displacement. So I used that displacement in W = (F*d)cos\theta as shown in post. Also...you're saying if I find the height, I can use mgh to find works? (That potential energy is equal to work)?

What is the minimum work needed to push a 1000 kg car up 45.0 meters up a 12.5 \circ degree incline? a. Ignore Friction b. Assume the effective coefficient of friction is 0.30. Work: W = (F*d)cos\theta Coefficient of friction: W = \muN(d) What I did: W = (m*g)(d)cos\theta...