Recent content by ecoli

  1. E

    How can I use math to calculate the distance of a trebuchet-launched projectile?

    Here's a simple Java algorhythm that I used when building mine. There is a downloable versio that a bit more user friendly that I like. http://www.algobeautytreb.com/javatreb.html
  2. E

    Uncovering the Truth: Why Do We Get Sick in Cold Weather?

    There's no evidence that cold directly causes disease. But cold influences your stress levels which definitely influences your immune system. It could also be that during the winter months stress level goes up for reasons other then cold.
  3. E

    Calc + applications in physics

    ahhh... thanks guys, all clear now.
  4. E

    Calc + applications in physics

    ok, thanks. first off, I have Fd = (800 + 2x) \int_{0}^{500} 800 + 2x dx then I pull out the 800 and get 800 \int_{0}^{500} 2x\ dx I integrate and get 800 * x^2 from 0 to 500 which is 200 million, and not the correct answer
  5. E

    Calc + applications in physics

    I am following your advice, I must be integrating incorrectly. That's making the answer come out wrong, so I thought it was the setup that was wrong. Of course that's not the case.
  6. E

    Calc + applications in physics

    the weight of the cable changes. I understand that is equal to the force. I see why your answer is correct, but it's not the same answer the book gives... unless I'm integrating incorrectly.
  7. E

    Calc + applications in physics

    Where did you get the 500 from... because won't that change when you pull the cable upwards? The book gives the answer as 650,000 ft-lbs, so I'm not sure your answer is right...
  8. E

    Calc + applications in physics

    you're right, I forgot to copy the first part of the message... namely the problem. I'm an idiot... sorry guys.
  9. E

    Calc + applications in physics

    I think I found a way to do this, but it's not working. The problem gives a cable weighing 2lb/fot, that is used to lift 800 lb of coal up a mineshaft 500ft deep. find the work I looked up the answer, which 650,000 ft-lbs. The weight is the force, so there is no need for the acceleration...
Back
Top