Recent content by Ed Boon

yes, did it again and got 349m which would put the pot energy at 5.1303E10 J and with one locomotive giving about 1E10 J it would be around 5, which is what the prof said would be around 5-6 thanks

(decided to use 20km/h for speed) so vertically it would be 20km*cos(1°) = 3.046km = .846 m (in an hour). pot energy = 15Mkg*9.8*.846 = 124,362,000 kg m^2/s^2 = (1 J = 1 kg m^2/s^2) =1.24362 E8 J (required to move over one hour) 1 locomotive = 4400 hp = 3,281,080 J/s * 3600 s/h =...

All the info in the question is typed above, which is why I'm kinda hesitant on some of "assumptions" because isn't it first required to know the speed and acceleration for these? I am aware that coal trains can reach up to 40-50 mph (if what I was reading was correct) so even if it were hard...

Homework Statement How many GE locomotives are needed to power a 15k tonne (note tonne not ton) train up a 1 degree grade. Ignore rolling friction and wind resistance. Locomotive traction power is 4400 HP/locomotive. Homework Equations 1 hp = 745.7 J/s * 4400 hp = 3281080 J/s and...

any equations would help

I am a college student working on a project, I was wondering if someone might share some info about the subject in the title. We are working with a freeze thaw cabinet and I am looking for equations/info on how much time the phase change will take at different surrounding temperatures for...

Homework Statement Homework Equations ? The Attempt at a Solution In our previous homework, this is the only problem I got wrong, I feel the book does a very poor job at explaining over this subject. I went to physics help room but because its summer the guy was only there for...

Homework Statement Homework Equations U=-uz*B=ml*(e*h/2*m)*B uz=-(2.00232)*(e/2*m)*Sz The Attempt at a Solution I thought this was very simple until I re-read it after solving. In the n=1 state for an electron isn't ml equal to 0? so U=0*stuff = 0 but then part b says is there...

Thats what I was thinking so you will have na*sin(theta of a) equals to both nb*sin(0b) and nc*sin(0c) (b and c the 2 refractions) so if u set the 2 equal to each other: nb*sin(20.5) = nc*sin(12) dont you need more info to get the exact values instead of just a ratio? thanks for the quick...

Homework Statement Homework Equations Snell's Law: na*sin(theta of a) = nb*sin(theta of b) wavelength = index of refraction / n n = c / v The Attempt at a Solution The only information given in the problem is the 2 angles of refraction and of course n of air is 1, I do not understand how to...