According to KCL and KVL, any node should result the same. Only difference is some nodes are appearing easier than other depending on how complicated they breach out from the node.Usually, I would select the node which will involve the least equations which will provide more convenient way to...
If your node 3 is at v_3, then where 3i_0 is in the equation?For the node 3, I would write the equation like 3i_0+4A=(v_3-v_2/1s)+v_3/2s. I think you may have missed the 3i_0 in your equation.
I would use KVL and the conservation of energy in a loop for a beginning.Since we know the value of each independent source, followed by convention sign we should be able to figure out how much energy left across the resistor. If the left energy is negative , then it is supplying the power. If...
When the voltage at the node n=the ideal voltage source, it looks like a short between tow points to me. A short, if the internal resistance is undetectable, then there is no energy loss which I will say it is possible for 5G1=0.
Some e-books that are creditable are mostly from your school or I would search the Google scholar website for the particular problem.
Another tip is to go the library and borrow books that say circuit analysis or circuit principle ,etc,.. They are everywhere since they are fundamental of...
There are two easy nodes that I used for the question.
First, the node on the top left conner below -2A,I got:
i_1=(v_1-v_2)/5+(v_1-0/20), assuming the -2A flowing into the node while the other two flowing out of the node.There's a point to note .When we assume the current flowing from the...
To solve a matrix with polar or rectangular elements in TI-84, is unlikely possible. I use TI-89 Titanium to solve this kind of problem. Or if you have access to matlab, you can use it to solve the problem.
If you can do it with current source, then you can definitely do it with voltage source. Just simply use the ohm law to convert the voltage to the current. For example, I=V/R, if You have the KCL equation,then just replace I variable with V/R by using ohm law.
You can use any node by using KVL and KCL rules.
You would probably come up with two simultaneous equations which I would prefer using some math software tools or advanced calculator to solve the equations.