Hmm I must've miscalculated when doing mesh then. I did mesh but my answer was 3mWb. I'm supposed to get the same answer as the way I did KVL right ?
I see. Thanks again man :)
Thank you !
I was able to get the answer :)
Here's what I did
*After finding the RC1, RC2, RC3 and Rgap
Φ3 is the flux that goes through the air gap
Using KVL:
Loop 1: -2000 + (RC2 + Rgap) Φ3 + RC1Φ1 = 0
15915.49 Φ3 + 397887.36 Φ3 + 39788.74 Φ1 = 2000
39788.74 Φ1 +...
I really appreciate your help, cn1995. I apologise if this question seem effortless to solve, but I am having difficulties with it.
I'm doing my mechanical degree first year but I have electric subjects as well.
Can you help me verify if
RCORE= 95480.6 1/H or 39789 1/H
?
I noticed that...
When the question says neglect fringing and flux leakage, it's safe to say that Φ = BcAc = BgAg right ? So can we also say that Ac = Ag ?
The problem now is, to get the MMF, I require the Rc and Rg, and Rg requires Ag that the question does not provide.
Otherwise, how do you suggest that I...
So we'd get the net flux of 2000AT which is only going in one direction clockwise right ?
Some of my buds were saying it's supposed to be parallel because both ends of the coil connects to each other.
1. Homework Statement
As shown above
Homework Equations
*Not too sure if they are relevant. Pretty sure there's more. We have textbooks from the library as references but we still can't quite figure it out :/
Φ = BcAc = BgAg
B = Φ/Ac = (Ni/R)/Ac
R = lc/(Ac.μ)
The Attempt at a Solution...
Yeaaa you made an error with the components on the vertical and horizontal directions. Drawing a diagram for the components always helps. Make it a habit to make sure your components are right.
Just a little curious. What formula did Sir Isaac Newton used to find out the exact value of Earth's gravitational force ? Can we apply that formula to find out the gravitational force of other objects ? Let's say, calculating the gravitational force that my bottle has or our body. I know that...
Thank you. I was going to ask how do I prove that there's no solution. So technically, switching the right hand side fraction to the left hand side isn't the solution, but making the statement beforehand by stating that the rational expression whereby x ≠ 3, then get my answer which is x = 3...
OH SHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH. OMFG. THANKS. I CAN'T BELIEVE I DIDN'T SEE THAT. KILL ME PLS.
EDIT : Oh umm umm, so that would mean that it's possible to bring a fraction to the other side like that ? *Haven't really done that in high school maths.
Question : [ x / (x - 3) ] + 3 = 3 / (x - 3)
Attempt :
So what I did was simplifying the left hand side of the equation,
[ x / (x -3) ] + (3 / 1) = 3 / (x - 3)
[(4x - 9) / ( x - 3) ] = 3 / (x - 3)
then bring the (x - 3) from the right hand side to the left hand side to multiply
[ (4x - 9)...