Recent content by Elsasw
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Residue theorem to solve integration
Contour? Does this referred to residues at z=ia and z=-ia?- Elsasw
- Post #3
- Forum: Calculus and Beyond Homework Help
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Residue theorem to solve integration
Hi all, i have an integral equation of ∫1/[(z+ia)^2 *(z-ia)]*exp(-p^2[(A+iBz)/(C(z^2+a^2))])*exp(-ikbz)dz from the limit of 0 t0 l I tried perform residue theorem but due to the 1/[(z+ia)(z-ia)] factor in the exponential term complicated it...I also tried incorporate L'Hopita rules in...- Elsasw
- Thread
- Integration Residue Theorem
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Undergrad Using L'hopital's rule in exponential function
Thank you very much HallsofIvy...i got what u meant.. -
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Undergrad Using L'hopital's rule in exponential function
Is that any way to find a finite value which is not equal to zero using L'hopital's rule in limit(z=-ia) exp[-A/(z+ia)]/(z+ia)^2 i kept getting 0/0 after differentiation Thank you -
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Graduate Integration with fraction in exponential
Thanks DH..Nop..it is not homework...its a part of my work...but thanks to you or i will be still trying to integrate it in terms of elementary function. -
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Graduate Integration with fraction in exponential
Hi all, am stuck with the integral with fraction in exponential The equation I=∫exp(bz)/(a+iz)*exp[(6*a^2-ik*w^2*z)/(z^2+a^2)]*dz I already tried to partial fraction the 2nd exponential term, then i tried to perform integration by parts but it doesn't work well.i tried substitution too... -
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Graduate Integration of exponential of inverse tangent
Thanks a lot mute... -
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Graduate Integration of exponential of inverse tangent
Thank you mute. I redid the initial equations and put the inverse tangent term as arctan (z/a) instead of arctan (z/a^1/2) as earlier.ignore the w as i already factor it out. so now i got I=∫A/[(z^2+a^2)^1/2]*exp(bz)exp(-i*arctan(z/a)) *dz... -
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Graduate Integration of exponential of inverse tangent
Hi all, i need help with integration of exponential of inverse tangent, could not find it in table of integrals the whole equation is I=∫A/[w(a+z^2)^1/2]*exp(zb)*exp[(-i*arctan(z/(a)^1/2)] -am trying to integrate by parts but stuck at the arctan part Thank you.