*Not an expert*
They don't mean 2 opposite corners of the entire grid do they? That would be a very different problem.
The current between any 2 nearby resistors would effectively be zero wouldn't it?
Follow-up: I chased the lecturer up again about this and another issue and he now 'agrees' with me. Thankfully my mark has improved from 55 to 75%. Pity about the other students affected..
Thanks. Yes, it is an exam question so although it is worth few marks I feel it is important to straighten out.
I suffered in this exam because I (almost) completed all three questions, then the lecturer realized the exam was too hard, so he decided to excise Q3 to be 'fair'... but...
Homework Statement
Hi Physics gurus, this question was in my Chem Eng exam, and I can't agree with my lecturer's answer. He makes a LOT of mistakes, so it's hard to know when he's being clever or reallllly dumb.
The question I have issue with is: "Is the pressure a manometric or an absolute...
OK thanks for all the replies, that's exactly what I thought. Actually I think I've got it now, but here's my reasoning (prepared earlier) and my solution at the end.
n.b, the references drawn in are mine, because we have been admonished enough times to give a magnitiude, unit and reference...
No not in the case of V(in)=-5V. They're effectively an open circuit. What I'm trying to understand is if the voltage is negative so therefore V(R2) is negative (using the polarity references I have drawn in) does it then follow that I (being V/R) =-2.5V/1k-ohm in the direction given, or does...
Only that as far as this introductory course is concerned, it doesn't exist!
I'm just trying to understand how to determine if the current through the resistor (#2) has a positive or negative value. Does it always have to be positive when entering the positive reference of the resistor?
1. I know this is really simple but I'm missing some little piece of the puzzle
No problem getting to vab=
+1.5V for a)
+1.5V for b)i.
-2.5V vor b)ii.
+0.5V for b)iii.
But what about current I?
2. I=V/R
3. so for IR2
b)i. I have 1.5V/1kΩ=1.5mA (sure I agreee with that)
b)ii. I have...
Hiya physics lovers, I've joined here because I've just started studying engineering but I seem to have gotten a lot less clever in the 20 years since studying last.
Look forward to some stimulating discussion!