Recent content by Emilio

At the top node, according to KVL, the net voltage should be 0=v1+v2. But here, the voltages are in the same direction, and are of different magnitudes so they don't cancel out. Does the dependent current source generate voltage as well? I thought it just changed the current.

Ah, so they push 240mA towards the lower node, with 4i1 leaving the node. And that would make i1=60mA. So then lower node = 0 = 180mA+60mA-4i1 = 180mA+60mA-4(60mA), which means it;s valid?

Homework Statement Homework Equations P=Vi The Attempt at a Solution For part a, it looks like the dependent current source (4i1) leads directly to i1, with nothing that could change it. This would mean the interconnection is invalid, right? I can't tell if this circuit is in series or in...

I had typed -∞ at first, but after considering it, I realized it didn't make sense so I changed it to 0. So I can't set Fx=0, but I want to get this value as small as possible. Do I set up a limit as Fx approaches 0?

So instead of ∑Fx,y being equal to 0, they should equal the smallest possible value? Wouldn't that be Fx=0 and Fy=0?

What does it mean to find a minimum? A minimum force that would keep it in equilibrium? The smallest possible resultant force?

Oh that's odd, I even see the phi in your quoted text. I rewrote it using the editor instead of copy-pasting symbols, so hopefully it looks a little more accurate.

Oh sorry, I see a degree symbol in my original post, not sure why it doesn't show up. I did set ϕ = to 31°, but I used 59° in my equations just because it was a little easier to visualize for me. I didn't think it would make a difference because sin(31)=cos(59).

I'm not sure what you mean, am I missing a step or did I leave something out? All it says in the prompt is "Set ϕ = 31° ."

Homework Statement If the resultant force acting on the bracket is required to be a minimum, determine the magnitude of F1. Set Φ=31° Homework Equations Fx=F(cos(θ)) Fy=F(sin(θ)) The Attempt at a Solution First I tried to find ∑Fx and ∑Fy ΣFx=0=200+cos(67.38)260+cos(59)F1x...