Recent content by emohunter7

okay thank you for your help :)

okay i see where i made my mistake..so the correct answer is x=3+(6^(1/2)) right?

you get the same answer i was just taught to solve for x first...so is my answer right or wrong??

yes i know that is why i made the equation equal to x and plugged 0 in for y

Conics! Help Please! okay i think i have solved this correctly...still a little unsure though... y=x^2-6x+3----find x intercept first i used complete the square---- y-3=(x-3)^2 then i solved for x---- 3+(y-3)^(1/2)=x then i plugged 0 in for y and got 3+(3^(1/2)) and 3-(3^(1/2)) is that...

TRIG~ Law of Sin - Law of Cos HELP PLZ! hey i need some help... so umm please help me

okay thank you

i got it :) thanks! new homework... will you help me with it if I have trouble?

ok... first i split sin3x making sin(x+2x) than i used the sum identity making (sinx)(cos2x)+(sin2x)(cosx) then i used double angle identity making (sinx)(1-2sin^2 x)+(2sinxcosx)(cosx) dunno what to do next

the problem is: sin3x = (sinx)(3-4sin^2 x) ...PROVE THAT THEY ARE EQUAL

then do I multiply the (2sinxcosx)(cosx) ?

so by using cos2x and sin2x formulas I should get (sinx)(1-2sin^2 x)+(2sinxcosx)(cosx)...right??

sorry I just need to know where I'm messing up.

do I then change the cos's to sin's?

alright as my next step I put (sinx)(cos2x)+(sin2x)(cosx)...is this correct?