Does this mean superposition gives extra merit to qubit in terms of the data capacity it can encode? Because the classical bit can only represent one of two states (1 OR 0) at a time.
Regarding to the superposition state --
Besides coexist in state
$$
\ket{0} AND \ket{1}
$$
Qubit can be in any state pointing the surface of the Bloch Sphere? Is that true?
"However, state #2 is not the only possible entangled state of two qubits"
This means, besides state #2, the other possible entangled state of two qubits is state #3?
2.
$$
\ket{\Psi_{AB}} = \alpha \ket{00} + \beta \ket{11}
$$
3.
$$
\ket{\Psi_{AB}} = \alpha \ket{01} + \beta \ket{10}
$$
Dear @PeterDonis,
Thank you very much for the reply, that's helpful.
I'm a first-time user... Now I'm investigating how to write the equation directly in this post. How about this?
Dear all,I have four questions. Hopefully, someone can answer. Thank you :)
1.
A qubit is described as a two-orthogonal basis state. How about two entangled qubits?
2.
What is the actual reason for a qubit cannot be cloned/copied?
Is it because without knowing the value of the complex...