Thanks!
mgh=mgh(2)-1/2mv^2(2)
I canceled out the mass because it should be the same throughout the equation and no mass is given, leaving me with:
gh=gh(sub2)-1/2v^2(sub2)
(9.8)(h)=(9.8)(28.5)-(1/2)(15.8)^2
9.8h=279.3-124.82
h=154.48/9.8
h=15.76
This answer seems illogical...
A roller coaster starts at height (h). It goes down this hill and then goes up a second hill that is at a height of 28.5 m at a speed of 15.8 m/s. How high was the initial hill?
Given equations:
U=mgh
KE=1/2mv^2
W=Fd
P=W/T
Honestly, we've never done a problem like this before and...