Recent content by encasements

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    Rate of change of pressure with volume, adiabatic vs isothermal conditions

    Thanks for your help. This is what I have so far: isothermal: PV = nRT => P = (nRT)/V => dP/dV = -(nRT)/(V^2) dP/dV = -2 x 10^7 => -(nRT)/(V^2) = -2 x 10^7 adiabatic: PV^(5/3) = k where k is some constant P = k/(V^(5/3)) => dP/dV = -(5/3)k/(V^(8/3)) I see that if I had...
  2. E

    Rate of change of pressure with volume, adiabatic vs isothermal conditions

    Homework Statement For a particular sample of monatomic gas, the rate of change of pressure with volume under isothermal conditions is -2 x 10^7 Pa m^-3. Calculate the rate of change under adiabatic conditions. Homework Equations isothermal: dP/dV = -2 x 10^7 Q = nRTln(Vf/Vi)...
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