The tables I was looking at were like that, but that wasn't the particular page I was viewing. But thanks for explaining it to me, as well, thanks a lot for that link. It like how it explains the history of primes and why they are imporant.
:smile:
So I just heard about the new prime number that was discovered and for some reason got kind of interested in it.
So I'm looking at prime number tables on various webpages that show the prime numbers, dates discovered, etc.
I'm confused on what the "digits" column in these tables means...
Thanks very much to everyone who posted to my questions. Everybody's reply helped be understand and solve the problem.
Thanks again, I really appreciate it!
I'm sorry. But I don't see the point your trying to get across here.
f(x) = ax^2
g(x) = bx^2
(f+g)(x) = (a+b)x^2
(sf)(x) = (sa)x^2
{where s is a scalar; a and b are coefficients)
Why doesn't this show that its closed under addition and scalar mult?
when you said:
"x^2 +...
I'm not sure what you mean by additive zero element.
And just so I'm clear, is 2x^2, for example, a degree 2 polynomial that would be in the set that the above question is asking?
i.e. degree 2 polynomials can still have coefficients, right?
I'm not sure I understand why this is.
So then the set of functions is only: ax^2
Is this what you mean? If it is, I'm still not sure why the set wouldn't be closed under addition and scalar mult. :
f(x) = ax^2
g(x) = bx^2
(f+g)(x) = (a+b)x^2
(sf)(x) = (sa)x^2
{where s is a scalar...
I'm really confused about a question I came across in my textbook.
It basically says this:
Consider the set of polynomial functions of degree 2. Prove that this set is not closed under addition or scalar multiplication (and therefore not a vectorspace).
I'm confused because I think it is...