Hi, I've been working on figuring out how to make each point in a plot a color specified by a function that I wrote. I was wondering if anyone knew how to do this in a single command. The only way i have though of making this work is with a loop that goes through each individual point and...
Homework Statement
A radar transmitter used to measure the speed of pitched baseballs emits pulses of 2.0cm wavelength that are .25micros in duration.
(a) what is the length of the wave packet produced?
(b)to what frequency should the receiver be tuned?
(c) What must be the minimum...
Thank you for the quick reply! Yeah, I know it is just like a command line, i guess I was looking for another window to execute commands. It was my plan to use the notebook as a place to write scripts and try out little chunks in a separate area.
But my data will definitely have fixed size. Is...
Hi,
Im a pretty decent MATLAB and maple user and now I am starting to use mathematica, because I've heard good things about it. I had some simple questions about it that I was hoping someone could answer.
1.) What is the best way to store data in mathematica? Do people use matricies like...
if I can write that then I clearly have a contradiction because the energy before is significantly larger than the energy after. am i moving in the right direction? once again thank you for helping me out.
So you're saying that there is no excitation. Why is that so? Didn't the electron absorb the photon (or at least some of its energy)?
So are you saying that now I can write:
=E_{\gamma}+\sqrt{E_{\gamma}^{2}+(mc^ {2})^2}=mc_{2}
by conservation of energy in the CM frame?
Before in CM:
E_{CM,before}=E_{\gamma}+E_{e}
E_{e}=\sqrt{(pc)^{2}+(mc^{2})^2}
but, the momentum of the electron is the same as of the photon
E_{e}=\sqrt{E_{\gamma}^{2}+(mc^{2})^2}
E_{CM,before}=E_{\gamma}+\sqrt{E_{\gamma}^{2}+(mc^{2})^2}
After:
E_{CM,after}=mc^{2}
How could I include the...
Homework Statement
The question asks me to prove that the photoelectric effect cannot occur with a free electron. ie. one not bound to an atom. A hint is also provided: Consider the reference frame in which the total momentum of the electron and incident photon are zero.
Homework...
Figured it out:
E_{i}=m_{p}c^{2}+m_{Li}c^{2}
E_{f}=2m_{He}c^2+2KE_{He}
KE_{He}=8.65MeV
I forgot to subtract off the rest energies in the very first post for some dumb reason!