Recent content by eno

it appears that I have punched in the wrong notation the whole time. ths for ur help.

Within 1 sec, e drifted for length L L = v * 1 sec = v total [B]e[B] drifted within 1 sec is 1 Ampere. 1.0 A = 6.24*10^18 e = 10^29 * v * ([FONT=Times New Roman]π * (0.001)^2) v = 2 * 10^-6 m/s therefore, does not match with the ans in the book.

i have tried it many times and it did not reach tat ans.

Copper has approximately 10^29 free electrons per cubic meter. What is the approximate average velocity of electons in a 1.0 mm radius wire carrying 1.0A? resisivity, p of copper = 1.68 * 10^-8 ohms meter The answer in the book apparently is 2 * 10^-5 m/s. Please help by showing all...

thx alot, gauravkukreja!

sorry, Raza, nice try. the 1176 is the force, and not the mass, so u cannot use the force of 200N to divide that force, which results in some unknown unit number. THe answer just conincidently matches with the ans int he book, but i am sure the way u got it is wrong...again, thanks for trying...

PLZ HELP! I am puzzled with this problem, and all i could find are that the forces equal, but the ans int eh back of the textbook clearly says the solution is 0.2 m/s2 Question: This situation occurs in a pulley system. A 80.0 kg man inside a 40.0 kg dumb waiter (like an elevator) pulls...