Recent content by erde

so for the second approach the correct way would be to say 1)##p_0 V_0= n_0 R_m T_0## 2)##4p_0 V_0= 4n_0 R_m T_0## ##\frac {2)}{1)}=\frac {4p_0}{p_0}=\frac {4n_0}{n_0}## so if ##m_{CH4}=m_{He}## => ##n_{CH4}=1/4n_{He}## 3) ## xp_0 V_== (4+1/4*4)n_0 R_m T_=## => ##xp_0 V_0=5n_0 R_m T_0## =>...

Homework Statement In a sealed container is Helium ##M_{He} = \frac {4kg} {kmol} ## with a pressure of ## p_{He} = 4bar##. now is Methan put isothermic inside the container till both the methan and the helium mass are equal( ##M_{CH4} = \frac {16kg} {kmol} ## Calculate using the ideal gas law...

thank you a whole lot, i have tried again and got ## 203.8 kW## which is indeed a little more. thank you a lot for your help!

i tried solving this equation for P in my calculator and got ##P=18.48 kW## which seems a bit too low as the energy required only for ##\dot m## is ## P=\dot m(h_V - h_L)=202.846 kW ## is that really the end result? also we didnt use the tip that ## \frac {du} {dt}= \frac {du}{dm} \frac {dm}{dt}##

1) dmL/dt=- ## \dot m ## -dmv/dt 2) in 1) dmL/dt=- ## \dot m ## + vL/vV*dmL/dt ## \dot m ##= vL/vV*dmL/dt - dmL/dt ## \dot m ##=[vL/vV-1] dmL/dt -> dmL/dt=## \dot m ## / ([vL/vV]-1) -> dmV/dt=## \dot m ## / ([vV/vL] -1) dmL/dt* uL + dmV/dt * uV = -## \dot m ## *hV +P ## \frac {\dot m} {...

volumen of the tank is V=0.1m3=const Mass at the start would be mV,1=m1*x; mL,1=m1*(1-x) the total Mass in the tank would be m(t)=m1- ## \dot m ## * t mV(t)=mV,1 - ## \dot m ## * t + ## \frac {P}{(h´´-h´)} ## *t mL(t)=mL,1 -## \frac {P}{(h´´-h´)} ## *t dmV/dt>0 dmL/dt<0 vL=const vV=const...

the exact statement of the question is: what value P has to have the electric heater H so that a constant vapor mass of 0.1kg/s leaves the container with h=2773.6 (tip du/dt=du/dm * dm/dt) take into account that during this exit process because of the continuous vapor formation the liquid water...

the prime values are the values for liquid water at the given pressure and the double prime are the values for the vapor at the given pressure, x is the amount of vapor. also for relevant equations, i tried to use U2-U1=-ΔM *h + P*t ΔM being the amount of water that leaves the container in this...

Homework Statement Hello, i have the following assignment due for monday and i have truly no idea how to tackle it, i have already tried it many times but all my results have been wrong. the problem is as follows. inside a sealed container is an amount of water: mass=90.26 kg; pressure 9.1842...