Thanks Deveno!
Ok, so since I had P, R and Q to start with, I should get two more parallelograms by adding two points a and b to P and R, and c and d to P and Q
PRab
a = R - RS = (1, 3) - (3, 1) = (-2, 2)
b = P - RS = (1, 1) - (3, 1) = (-2, 0)
PQdc
c = P - PR = (1, 1) - ((1, 3) - (1, 1)) =...