Recent content by esoteric deviance

Homework Statement Find the value of the derivative of the inverse of the function. Given that f(x) = (4^√x) - x + 3, find (f^-1)'(3). Homework Equations The Attempt at a Solution I know that to find the inverse derivative, one should switch the x and y's and then take the derivative, but...

Homework Statement http://www.fileden.com/files/2006/11/15/381656/19.39.png The figure shows a hypothetical speed distribution for a sample of N gas particles (note that P(v) = 0 for speed v > 2v0). (b) What is the value of vavg/v0?Homework Equations vavg = int[vP(v)]dvThe Attempt at a...

so what you're saying is: (change in d1) = (change in d2), v1 = v2, and a1 = a2? the equations for CM of velocity and acceleration: vcom = (m1v1 + m2v2)/(M) acom = (m1a1 + m2a2)/(M) i don't know what to do...if i set the velocities and accelerations equal to each other, all i end up...

Yeah, I guess I'm pretty lost. For some reason, the more I try to think about this problem, the more confused I seem to become :(. I hate to ask this, but might you be willing to give me a step-by-step explanation of how to solve it? I don't know if they have any significance (or if they are...

so if the only external force acting on the system is gravity, then Fnet,system = Mg = (m1 + m2)g = 9.8?

Still not sure what to do, sorry :(.

http://www.fileden.com/files/2006/11/15/381656/My%20Documents/problem%2013.jpg The figure above shows an arrangement with an air track, in which a cart is connected by a cord to a hanging block. The cart has mass m1 = 0.600 kg, and its center is initially at xy coordinates (-0.500 m, 0 m)...

thanks :smile:

so these are the points right|-----5.5 cm-----|--1.5 cm--| 1 2 (that 2 should be at the end of the line) point 1 = initial point 2 = final so i get: initial PE of spring + initial KE of cork = final PE of spring + final KE of cork is that right?

the thing is that I'm not sure how to do that. is it something like KE of the cork = final PE of spring - initial PE of spring?

but wouldn't the values be different since the change in x when it's compressed is 5.5 cm and the change in x when it's stretched is 1.5 cm?

the PE of the spring when it's compressed?

Still don't know what to do lol. Unfortunately, I might need a bit more than a hint on this one. Sadly, I've been trying to figure it for the past 45 min to no avail :(. Maybe if you could show me how to set up the conservation thing and explain the reasoning behind it...

A spring is compressed by 5.5 cm and used to propel a 3.8 g cork from a cork gun. k = 10 N/m. A) What is the speed of the cork if it is released as the spring passes through its relaxed position? B) Suppose, instead, that the cork sticks to the spring and stretches it 1.5 cm before...

Ah, okay :smile:. Thanks for the help ^_^.