I am working on this individually so its not a work related item. So i wouldn't get the support i would if I had a company with more order opportunities. I noticed i have been having a lot of troubles with vendors for that reason.
I like to use my vendors to help me with my designs in that...
Hello guys, I am relatively new here. I hope to spend more time here helping and receiving advice more often. Currently i have some questions with Love-joy couplings.
I have an application where i need to remove a shaft and replace it on the fly with ease. I looked for all kinds of...
Thank you for the response pongo38. You have been a lot of help for me on here. We spoke before i was using a formula that involved calculus and dx and integrals and i hadn't studied calc yet. I'm in the middle of calc 1 now and am grasping the concepts a lot better we are working with dx and dy...
My problem is proving my structure is sound. Currently i want to know my deflection from my loads applied.
See attachment. My load is 4000 lb. My carriage weight is 1200 lb. My upright column or tube is a 6" x 4" x 1/4" structural steel which i have 2 of these. I have distances to my CoG...
now my delima is by using new method i lessen the gap from the bearings and load which allows me to instead of making frame adjustable with telescoping tube (i was in process of designing in as you see in new pictures) I can leave at a span of 2 meters (widest belt) and allow them to run any...
Well, i have found a flaw in the design (A1) i just posted about requardless of this calc. The collars on each side will be impossible to remove once i wind belt. I will have to go with something like A4 and A5 with rollers inside a housing that the shaft sits on so they can remove the collar...
I have an application where I have a shaft being supported from end to end with bearings (self aligning) and a motor hard mounted driving it. The shaft starts at 1 3/4" RD to accept motor and bearings. Then is welded to a 2" x 1/4" square tube for the output. It allows for a wooden roller to be...
I understand dx now watching youtube videos. They are very helpful. Now if i can make my funtion Mm I can then find the derivative of my Mm funtion and plug in x=21.75 then divide by EI. This would be correct right?
Thanks for the post, I havnt gotten the time to investigate it to much farther yet. But that night I had my last post I recearched dx and i understand the concept i just need to put it together. Which i need my equation to determine. What i read and i will do more research for a better...
Im pretty determined and i am pretty good with numbers so I am researching dx and am going to figure out how to use it. However, could u help me by writing a formula for my M moment so i can work with it and determine how you created it? Or, if not could you lead me to a site or book that might...
With further investigation with another beam I tried using this method and compared it to the equation I have and it is not working.
Trying to figure it out but I am burnt out for the day. Have to investigate with a fresh mind.
Okay, I investigated this more with your recent post and here is what I gathered.
I know when I have a supported beam at both ends with a load in the center I have a formula of Pl^3/48EI. With that being said I have a coefficient of 1/48 right?
I calculate my area of my M diagram...
I got this information from a different forum. I asked a question but i was banned because I told them i was still learning in school. Apparently you can't post there if your not "an engineer"
Does anyone understand how to do this? Very simular to what we have talked about here...
Yes, I did the calc out of my mechinery's handbook and got the same .0973" at center. So its in the middle of what we are both gathering. Can anyone else enlighten us with our formulas and what we might be doing wrong?