Recent content by estex198

Rusty: So your logic is that since two rows will be filled in (n + n), the diagonals will equal the remaining number of lines minus two, with the exception that one of the lines will be one less (n-2) + (n-3), since it will intersect with the other line. Thanks a million btw for a clear and...

While I know the answer to this problem, I can't figure out *how* to get it. Carmelo has been commissioned to create a decorative wall for the 21st Annual X Games consisting of a square array of square tiles in a pattern forming a large X. The following example shows a pattern with 5 rows and...

Thanks! You really made this easy... Since I'm trying to get better at trig equations, I hope you don't mind my next question... Is there is another way?

For the first quadratic in #4 i have "-1 +- sqrt(2)" How can I find exact angles from these in radians??

tan22x - 1 = 0. Find all solutions from 0 to 2pi 1.) sqrt(tan22x) = sqrt(1) 2.) tan2x = +- 1 (reason for two quadratic equations in #4) 3.) use double angle identity for tan and rationalize to form two quadratic equations: 4.) tan2x + 2tanx - 1 AND tan2x -2tanx -1 5.) now I use quadratic...

Forgive me, I meant to say I see y=0 at 6 points. Thanks for reminding me of the domain.

Ah. Ok. So going over the exact key strokes, it looks as if I wasnt putting 100pi in parenthesis. Looks like it was dividing 100 and then multiplying the result by pi. Sorry for wasting your time.

Ok great! So now I see y=0 (or roots as you refer to them) at 7 points. Thanks for the help!

Is that graph plotted using radians? Still it looks like 7.

Im trying to determine the exact solutions (in degrees) to the trig equation shown below. I'm only interested in solutions over the interval [0, 360) . In my ti-83+, I input the function as y= 6(1/cos(X))^2*tan(X)-12tan(X). If I already know the number of solutions is 6, how can I tell this from...

If the problem is due to a calculator error, what more is there to do? It looks as if the correct answer is 6.4094 * 10^-4. Thanks for your help!

Wow, that is interesting. I reset all RAM and ensured the OS was the latest version available from TI (1.19). Still getting same result. Perhaps its time to upgrade my adding machine... Thank you all for your help!

Forgive me for the typo. I mean inverse sine function. And yes, I've checked and rechecked that my calculator is in radian mode.

Problem: Solve for t, 20 = 100 sin 2pi(50)t note: pi = "pie" I must be doing something wrong here. To solve algebraically, I first divide both sides by 100. Then, I get the inverse cosine of both sides, and set the angle in radians (.2013579208) equal to "2pi(50)t". Lastly I divide the derived...