Recent content by EvanQ

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    Finding the Position and Charge for a Zero Resultant Force in Coulomb's Law

    alright got it now, thanks a lot for your help. i was about 80% through typing out my reworking to see if you could check it when i accidentally clicked the back button on my mouse and lost it all, and i really can't put myself through typing it again lol.
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    Finding the Position and Charge for a Zero Resultant Force in Coulomb's Law

    Homework Statement Three point charges lie along the x axis. A positive charge q1=16.0mC is at x=2.00m. Another positive charge q2=9.00mC is at the origin. Where should we put a third charge so the resultant force acting on it is zero? What should be the sign of the charge? Homework...
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    Solving Sliding Wire Problem: Determine Magnitude & Direction of Current

    really confused sorry :(
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    Solving Sliding Wire Problem: Determine Magnitude & Direction of Current

    9.8Msin180=ILBsin90??
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    Solving Sliding Wire Problem: Determine Magnitude & Direction of Current

    and the current would go to the left, determined by the right hand rule?
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    Solving Sliding Wire Problem: Determine Magnitude & Direction of Current

    ok so force pulling the wire down: F=masinθ = -9.8Msinθ so for the rest: F=ILBsinθ 9.8Msinθ=ILBsinθ 9.8M=ILB I=9.8M/LB ??
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    Solving Sliding Wire Problem: Determine Magnitude & Direction of Current

    Homework Statement A straight piece of conducting wire with mass M and length L is placed on a frictionless incline tilted at an angle theta from the horizontal. There is a uniform, vertical magnetic field vecB at all points (produced by an arrangement of magnets not shown in the figure)...
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    How Does a Bent Wire Affect the Magnetic Field at a Point?

    ΔB = μo/4π(IΔLsinθ)/R^2 so I = 27 θ = 45 ΔL = 2mm? and R can be found using trig. so what is μ and o?? soz just really lost. any help would be great.
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    How Does a Bent Wire Affect the Magnetic Field at a Point?

    Homework Statement A wire carrying a 27.0A current bends through a right angle. Consider two 2.00mm segments of wire, each 3.00cm from the bend. Find the magnitude of the magnetic field these two segments produce at point P, which is midway between them. Homework Equations F =...
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    What is the Magnitude of the Magnetic Field for a Proton Beam?

    that was correct :) thanks heaps for your help
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    What is the Magnitude of the Magnetic Field for a Proton Beam?

    r = mv/qb 0.008276 = (1.67x10^-27 x 1200) / (1.602×10^−19 x b) (1.602×10^−19 x b) = (1.67x10^-27 x 1200) / 0.008276) (1.602×10^−19 x b) = 2.42146x10^-22 b = 1.5115x10^-3
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    What is the Magnitude of the Magnetic Field for a Proton Beam?

    would i be correct in saying that using the arc length formula: pi/2 radians is equivalent to 1.3cm θ = s / r r = s / θ = 1.3 / pi/2 r = 0.8276 cm t = 0.013m / 1200m/s = 1.083x10^-5 s then w = θ / t = (pi/2) / 1.083x10^-5 = 145041.2121 w = w0 + at 145041.2121 = 0...
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    What is the Magnitude of the Magnetic Field for a Proton Beam?

    yeh i was about to ask how you knew the radius. ok i'll work on those and get back to you in a few mintues. **digs deep into the memory bank for equations**
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    What is the Magnitude of the Magnetic Field for a Proton Beam?

    i got 1.129x10^-13 and failed my first attempt.
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    What is the Magnitude of the Magnetic Field for a Proton Beam?

    ok so: F = qv x B B = F/qv = F / (1.602 × 10^−19) x 1.2 (charge of a proton x velocity of proton) F = ma? = 1.67x10^-27 x a (mass of a proton x acceleration) however, as: m(v/t) / q(v) = m(1/t) / q = (1.67x10^-27 x (1/t)) / 1.602 × 10^−19 (where t = distance / velocity??)