Recent content by eXSBass

I understand it now! Thanks alot! It actually makes a lot more sense now! Cheers!

RHS :confused: - Edit, right hand side!

I'm sorry. Its not homework. I just need to know how for an exam. When I complete the square I get: Well, this is what I've got on my sheet. I just don't understand step three! ax²+bx+c=0 1 a[x²+bx+c]=0 --> x²+(b/a)x+c/a=0 2 (x+b/2a)²+c/a-b²/4a²=0 --> (x+b/2a)²=b²/4a²-c/a 3...

Hi! I'm new here so if this has been covered please accept my apologies. I'm having trouble proving the equation from: ax²+bx+c=0 to the solutions x=(-b(+/-)√b²-4ac)/2a I've been told to complete the sqaure of ax²+bx+c, then rerrange to give x, but I just can't get it! If you could show the...