- #1
eXSBass
- 4
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Hi! I'm new here so if this has been covered please accept my apologies.
I'm having trouble proving the equation from:
ax²+bx+c=0 to the solutions x=(-b(+/-)√b²-4ac)/2a
I've been told to complete the sqaure of ax²+bx+c, then rerrange to give x, but I just can't get it!
If you could show the steps you took to get there it would be very helpful too.
Any help would be appreciated. Thanks
I'm having trouble proving the equation from:
ax²+bx+c=0 to the solutions x=(-b(+/-)√b²-4ac)/2a
I've been told to complete the sqaure of ax²+bx+c, then rerrange to give x, but I just can't get it!
If you could show the steps you took to get there it would be very helpful too.
Any help would be appreciated. Thanks