Recent content by eyespy

So, I will calculate q'a + qb = qa = CaVa--> q'a/Ca - qb/Cb = 0 --> q'a/Ca = qb/Cb. So CaV - q'a = q'aCb/Ca, manipulating q'a = Ca²V/(Ca+Cb). And I found that q'b = VCaCb/(Ca+Cb). Now what I have to do? I was making this exercise for more than one day lol

It is when the voltage is equal in Capacitor A and B. They are in parallel or in serie?

To solve this question first I calculated the potential energy the capacitor A stored. It's equal a: Ca.V²/2. Ok, so when switch S1 is open and S2 is closed I calculated the equivalent capacitance as if they were in series --> 1/Ceq = 1/Ca + 1/Cb --> Ceq = (Ca.Cb)/(Ca+Cb). So I used the formula...

Thanks, I think tha I got the direction :)

If the platform consumes part of the energy of the ball, why is it higher in the second case? Sorry, I don't know how to calculate the horizontal energy conservation. I found this exercise at EJU (Examination for Japanese University Admission for International Students). I'm going to the 3rd...

Honestly I do not know. To find out the height in the first situation I simply used energy conservation, as it can reach a certain height was easy. The problem was in the second case, I did not understand how the fact that the platform is free can change the height. Does the platform move along...

Me too, but in feedback the answer is: (M / (m + M)). So h/H = (M/(m+M))

Homework Statement:: Consider a platform (mass: M) which horizontal surface AB s smoothly joined to vertical surface CD as shown in the figure below. Initially, the platform is fixed in place on a horizontal floor. A small object (mass: m) is placed on AB and given an initial speed of v in the...

What I must to know to resolve this exercise? Thanks