Great! Thanks. So how do I calculate the coefficient of static friction from the radial acceleration/force? Is the force acting on the coin in the opposite direction of the radial acceleration considered "n", the normal force?
[b]1. A coin placed on a 12" record will revolve with the record when it is brought up to a speed of 33.33 rpm. Provided the coin is not more than 4" from the axis...
[b]2. a) What is the coefficient of static friction between the coin and the record?
[b]3. I have calculated the...
The package fell 3000m at an acceleration of -9.8m/s^2 with a Vi of 0. Just divide the displacement (3000m) by a = -9,8m/s^2 and it give you the time it took the package to hit the ground in s^2. Then take the square root to obtain s.
d = a x t^2
3000m = -9.8m/s^2 x t^2
3000m / -9.8m/s^2 =...
Try;
Time for package to hit the ground.
3000m / -9.8m/s^2 = 306.12s^2 = 17.5s
Position of the plane at t = 17.5s, (time it takes for the package to hit the ground.)
17.5s x 275m/s = 4812.5m
Position of the package at t = 17.5s
Xf = Xi + Vi(t) + 1/2a(t)^2
Xf = 0 +...
1. The motion of a body falling from rest in a resistive medium is dv/dt = Bv - Av^2.
2. Find it's initial acceleration.
Find the velocity at which the acceleration becomes zero.
3. B and A are constants.
dv/dt = acceleration = Bv - Av^2.
vf = vi + at
vf = 0 + Bv - Av^2(t)
vf...
1. The motion of a body falling from rest in a resistive medium is dv/dt = Bv - Av^2.
2. Find it's initial acceleration.
Find the velocity at which the acceleration becomes zero.
3. B and A are constants.
dv/dt = acceleration = Bv - Av^2.
vf = vi + at
vf = 0 + Bv - Av^2(t)...