Recent content by eyvhgi557r

Great! Thanks. So how do I calculate the coefficient of static friction from the radial acceleration/force? Is the force acting on the coin in the opposite direction of the radial acceleration considered "n", the normal force?

[b]1. A coin placed on a 12" record will revolve with the record when it is brought up to a speed of 33.33 rpm. Provided the coin is not more than 4" from the axis... [b]2. a) What is the coefficient of static friction between the coin and the record? [b]3. I have calculated the...

The package fell 3000m at an acceleration of -9.8m/s^2 with a Vi of 0. Just divide the displacement (3000m) by a = -9,8m/s^2 and it give you the time it took the package to hit the ground in s^2. Then take the square root to obtain s. d = a x t^2 3000m = -9.8m/s^2 x t^2 3000m / -9.8m/s^2 =...

Try; Time for package to hit the ground. 3000m / -9.8m/s^2 = 306.12s^2 = 17.5s Position of the plane at t = 17.5s, (time it takes for the package to hit the ground.) 17.5s x 275m/s = 4812.5m Position of the package at t = 17.5s Xf = Xi + Vi(t) + 1/2a(t)^2 Xf = 0 +...

1. The motion of a body falling from rest in a resistive medium is dv/dt = Bv - Av^2. 2. Find it's initial acceleration. Find the velocity at which the acceleration becomes zero. 3. B and A are constants. dv/dt = acceleration = Bv - Av^2. vf = vi + at vf = 0 + Bv - Av^2(t) vf...

1. The motion of a body falling from rest in a resistive medium is dv/dt = Bv - Av^2. 2. Find it's initial acceleration. Find the velocity at which the acceleration becomes zero. 3. B and A are constants. dv/dt = acceleration = Bv - Av^2. vf = vi + at vf = 0 + Bv - Av^2(t)...