Recent content by Failure007

Makes perfect sense, thanks so much.

First of all thanks for responding, what I'm still sort of confused about is if I plugged those parameters into their respective equations i.e. [x,y,z] = [4,8,-1] + -1[2,3,-4] = [2, 5, 3] for line 1 [x,y,z] = [7,2,-1] + 1[-6,1,2] = [1, 3, 1] for line 2 would that mean that those aren't the...

Homework Statement Find the vector, parametric and symmetric equations of a line that intersect both line 1 and line 2 at 90°. L1 : x = 4 + 2t y = 8 + 3t z = -1 - 4t L2 : x = 7 - 6t y = 2+ t z = -1 + 2t Homework Equations \vec{a}1 - \vec{a}2 + \vec{b}1t - \vec{b}2s...

Will do, Thanks a lot Doc Al.

If I'm understanding this correctly, could I assume that Vx=0.6428F and Vy=0.7660F and use those directly in my (150 + vx)^2 + (0 + vy)^2 = 40000 equation or would I have to use Fcos(50) and Fsin(50) instead? Thanks for the help so far.

Homework Statement Two forces act on an object at an angle of 50°. One force is 150 N. The resultant force is 200 N. Find the second force and the angle that it makes with the resultant.Homework Equations Ux=|U|cos(theta) Uy=|U|sin(theta) The Attempt at a Solution Basically I began by...

Sorry, I didn't know how to include the triangle in the question so I just called it delta, but what I was having trouble with was finding the work to move from the initial displacement to the delta displacement. So basically I figured there was an initial displacement vector that I had to find...

So if I multiplied [4, 7, 1]*[5,3,8] and got 49 as my dot product, then that's how much work is needed to result delta S = [5, 3, 8]? Why would they even mention the delta in the first place, because that's the only reason I assumed this question was difficult...

Hey guys, I normally don't use forums for help but I've been stuck on these questions for some time now and I just want to see if there's anyone out there who can set me in the right direction. These questions are from a grade 12 Calculus and Vectors class and they relate to the cross product...