Homework Statement
Two blocks are positioned according to the figure. Block A (80 lb) is attached to a rope as such that it doesn't slide or fall from block B (120lb). Compute the smallest value of Force to be applied on Block B for it to not move parallel to the inclined plane...
Truss Analysis :(
Homework Statement
Find the force on each of the members and tell if it is tension of compression.
Homework Equations
M = fd \sumFx and Fy = 0
The Attempt at a Solution
Well, my professor said to us that the first thing to do is to compute for the...
ah.. ok I get it! let me try again
For Reaction on B:
Set A as pivot, then total 3 moments (W CG and Wind)
W(1.5) + CG(7) + Wind(13) = Moment WCG
then to find RXN on B
Force B = Moment WCG/8.5
= 4559 lb
am I right?
hmm.. ok let me try again :D
For Reaction on Point B:
I'll set A as pivot, then total the Moment of W and CG.
W(1.5) + CG(7) = Moment WCG
then I'll divide it by 8.5 to get Reaction on point B? then B = 2724 lb
so I will ignore wind load completely on calculating Rxn on B?
or I will use...
The problem is... I don't know how should I get Rxn on point B...
but anyways, I tried it using this calculations..
First I set point A is the pivot. Then I totaled the 3 moments (Weight, CG, and wind).
W(1.5) + CG(7) + Wind(21.5) = Moment A
Then I divided it by 8.5 (the distance from A to...
sorry for the late reply, been busy...
ok here's what I did.
For Reaction on point A:
I replaced the 2 forces (W and CG) with a single force positioned at point A using this equation..
W(7) + CG(1.5) = F(8.5) F = 2,440 something.
Then I reduce the Moment of that F by the Moment of the wind...
sorry but it's 11:30 pm here already.. got to sleep, have class tomorrow.
Thanks for replying though, and thanks for correcting that 13 ft thingy.
Ill try to post my calculations tomorrow.
Homework Statement
The supporting structure of a billboard is attached to the ground by a pin at B, and its rear leg rests on the ground at A. Friction may be neglected. Point G is the center of gravity of the billboard and structure, which together weigh 2,800 lb. To prevent tipping over in...