Recent content by Fanjoni

The frictional force opposing movement is 0.57*(229 + 261)N =279.3 N ma = 372.7 - 279.3 = 93.4 Newtons,the mass is 229/9.8 = 23.4 Kg a=93.4N/23.4Kg = 4 meters/sec^2 Since at^2/2 = distance ----------> sqrt(2*distance/a) = t = 1.58 sec yes yes i finaly got it thanks guys

i found acceleration 15.74 and then found time to be 1.694s is this correct?

A box of books weighing 229 N is shoved across the floor by a force of 455 N exerted downward at an angle of 35° below the horizontal. (a) If µk between the box and the floor is 0.57, how long does it take to move the box 5 m, starting from rest? (b) If µk between the box and...

A freight train has a mass of 4.5*10^7 kg. If the locomotive can exert a constant pull of 15*10^5 N, how long would it take to increase the speed of the train from rest to 85 km/h? I know u need to use F=ma but how do i find time

Oh it was that easy. I was kinda thinking to hard Thanks BishopUser

An 1520 kg car is moving to the right at a constant velocity of 2.94 m/s. (a) What is the net force on the car? (b) What would be the net force on the car if it were moving to the left? any help i tried using Force=Mass*Acceleration I also don't know what it wants me to dod when...

would the horizontal componant be 65m/s and the vertical component be 70.04m/s I am not sure i f it is right

so far i have founf the time for the bomb to fall which is 7.14s using x=VT+gT^2/2 I also found how far it travels which is .464km But i don't know how to find the vertical and horizontal components and where the helicopter is when the bomb hits the ground

A military helicopter on a training mission is flying horizontally at a speed of 65.0 m/s and accidentally drops a bomb (fortunately not armed) at an elevation of 250 m. You can ignore air resistance. How much time is required for the bomb to reach the earth?(s) How far does it travel...

Thanks i finaly got it it took me a while This is what i did 185*sin55 =V(ertical speed) V/g = T(ime to stop vertically) T*2=total time 185*cos55 = v(horizontal speed) t*v=R(horizontal range) I did the same for the moon g = 1.6 Thanks

A pistol that fires a signal flare gives the flare an initial speed (muzzle speed) of 185 m/s. (a) If the flare is fired at an angle of 55° above the horizontal on the level salt flats of Utah, what is its horizontal range? You can ignore air resistance. (b) If the flare is fired at the same...