A military helicopter dropa BOMB

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Homework Help Overview

The discussion revolves around a physics problem involving a military helicopter that drops a bomb from a height of 250 m while flying horizontally at a speed of 65.0 m/s. Participants are exploring the time it takes for the bomb to reach the ground, the horizontal distance traveled during the fall, and the components of velocity just before impact.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of kinematics formulas to determine the time of fall and horizontal distance. Some express uncertainty about calculating the vertical and horizontal components of velocity and the helicopter's position when the bomb hits the ground.

Discussion Status

The discussion is active, with participants sharing their calculations and questioning assumptions. Some guidance has been offered regarding the calculation of horizontal and vertical velocities, but there is no explicit consensus on the correctness of the values derived.

Contextual Notes

Participants are working under the assumption that air resistance can be ignored, and there is a focus on using kinematic equations. One participant mentions a humorous observation about the helicopter following the bomb to the ground, highlighting the independence of horizontal and vertical motion.

Fanjoni
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A military helicopter on a training mission is flying horizontally at a speed of 65.0 m/s and accidentally drops a bomb (fortunately not armed) at an elevation of 250 m. You can ignore air resistance.

How much time is required for the bomb to reach the earth?(s)

How far does it travel horizontally while falling?(km)

Find the horizontal and vertical components of its velocity just before it strikes the earth.(m/s)

If the velocity of the helicopter remains constant, where is the helicopter when the bomb hits the ground? height above ground(m):confused: :mad:
 
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You need to show us some work first before we can help you. What have you tried so far, where are you getting stuck?
 
Use regular kinematics formulas and you'll be fine
 
so far i have founf the time for the bomb to fall which is 7.14s using x=VT+gT^2/2
I also found how far it travels which is .464km

But i don't know how to find the vertical and horizontal components and where the helicopter is when the bomb hits the ground
 
Now calculate the horizontal velocity from horizontal distance and time

and

the vertical velocity from vertical distance and time
 
would the horizontal componant be 65m/s and the vertical component be 70.04m/s

I am not sure i f it is right
 
Last edited:
Without grabbing a calculator, 70.04 sounds reasonable after doing some mental math (I usually use g=10m/s^2; after 7 seconds, the velocity is 70 m/s down, average velocity is 35 m/s down and distance is 7s*35m/s = 245 meters down; so your answer sounds quite reasonable.)

You could have also used v_f^2 = v_i^2 + 2ad for the velocity calculation, rather than relying on that intermediate step (although the time was asked for, so you had to find it anyway.)

If you have a physics teacher with a nice sense of humor, point out that the helicopter is going to follow the bomb all the way to the ground if there's no air resistance :)
 
view the video of the B-52 dropping bombs

I'm on dial-up, so I'm not going to wait 14 minutes for this video to load. However, I think it's the correct video that I use in class to demonstrate the answer to your question. Hopefully it helps you understand the independence of horizontal and vertical velocities. i.e. note where the bombs are as they fall in relationship to where they came out of the B-52. This isn't a star trek model where everything is hanging from strings and the background is moving... :)

http://www.danshistory.com/b52.html"
 
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