Recent content by fatcrispy

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    Cesaro Sum. Understanding the sequence.

    Big "oh..." moment. I think I misread the problem. It asks "what is the Cesaro sum of the 100th term sequence (1, z1, ..., z99)?" I realize now that it is the whole 100 term sequence and I don't actually have to go up to z100 right? Because the 1 in front makes it 100 terms. I understand...
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    Engineering, Photography, or Film? Which Career Path Should I Choose?

    I was thinking film due to it's creativity factor. But, I found out engineering requires a lot of creativity as well. So, with all the math I've taken I might as well go for it. Though, the particular major I choose will help determine where I move to and hence what university to apply to...
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    Cesaro Sum. Understanding the sequence.

    So, putting 1 in front of the sequence allows z99 to become the 100th term? But it isn't the 100th nth term right? With what you said it would just be 1980.01 as the answer? I am trying to fundamentally understand this. I understand it's just an average but when they start saying the value of C...
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    Engineering, Photography, or Film? Which Career Path Should I Choose?

    I've thought about being a photographer, film director, actor, engineer, physicist, mathematician, pilot, entrepreneur, etc... But I can't pick. My personality type is INTP which means I like working alone and on my own projects. With that in mind and my interests I think a Photographer...
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    Cesaro Sum. Understanding the sequence.

    Homework Statement I have a finite sequence Z=(z1,...,zn). The Cesaro sum of Z is \frac{(B1+B2+...+Bn)}{n} BC=z1+z2+...zC (1\leqC\leqn) Lets say the problem asks "The Cesaro sum of the 99th term sequence of (z1,...,z99) is 2000, what is the Cesaro sum of the 100 term sequence (1, z1,...,z99)...
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    Solving two absolute value variables.

    Could someone please help me finish this problem? Mark, thanks for everything!
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    Solving two absolute value variables.

    Oh, well in that case I got A=43/5 and B=-11/5. Thus, A+B=32/5 ? and that is the only answer right?
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    Solving two absolute value variables.

    Right? (A-B+2)/2 gives me the value of A+B? Nothing else would be the value right? I appreciate your help.
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    Solving two absolute value variables.

    So, it seems that II is the only one without a contradiction. So, does that mean I only use A=(15-B)/2 and B=(A-13)/2 ?? And just add them A+B=(15-B)+(A-13) / 2. So, my final answer will be (A-B+2)/2 = A+B?
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    Solving two absolute value variables.

    Homework Statement Given: |A|+A+B=15 and A+|B|-B=13. What is A+B equal to? Give all possibilities. Homework Equations The Attempt at a Solution I solve for both absolute variables. So, A=15-A-B or A=A+B-15 and B=13-A+B or B=A-B-13 Firstly, I solve for A. A+A=15-B...
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    Properties of exponents and logs problem

    Ok so I got a funky answer. 2y24+22y26=224 B=2y So, 16B+64B2=224 4B2+B=14 I ended up with B=-2 but that doesn't make sense with -2=2y
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    Properties of exponents and logs problem

    I'm still having trouble. 2y=z and y+4=log2Z and y+3=log4R? What do I do with this? Could you help me solve it please I am kind of lost. I get Z + R = 224 and B = 2Y Now what?
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    Properties of exponents and logs problem

    Find B when given: Y = log2B and 2y+4 + 4y+3 = 224 I could use some help figuring out the process to this. Thanks
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