Recent content by Fatimah202

thank you very much actually I was working on a computing and I forget some details on the statistical basics .. I didn't take a course on the probabilities tank you :)

sorry, I forget the conditional probability :( P(x1=2|x2=1) =P(x1=2 ∩x2=1) / P(x2=1) P(x1=2 ∩x2=1) = 1/16 P(x2=1)= 5/15 P(x1=2|x2=1) = 1/5 correct? ________________ you divide by two instead of multiply ! I was double it and get P= 1/4 instead of 1/16 !

cool ! that take us to say p(x2=1) = 1/4 is not like this ?

is the tree that I made wrong ? b. The probability that x1 = 2, given that x2 = 1. I will explain the calculations: p(x1=2) = 0.25 p(x2=1)= 0.5 but because the first generation get 2 particles I will multiply it by 2 2(0.25*0.5) = 0.25 where is the mistake exactly ?

why you are looking for the probability of getting zero particle ? for part b .. I would say that when x1=2 and x2=1 p= (0.25 * 0.5) +(0.25 *0.5) = 0.25 right ?

well, the problem ask for the probability of getting number of particles in the second generation more than zero ... not equal to zero right ? so I sum up all the probabilities of getting 1 particle and 2 particles in second generation .. I will highlight the path in the attached photo I get...

how about this ? and for part b : P= 25% PeroK .. thank you very much :)

https://fly.cloud.photobox.com/2984919587ea968d6b9e99fdd1b96c87d958717a3c978173f83c89a622c049a69cc2da81.jpg is this correct ? I think I should not calculate the zero particle ,, right ?

Homework Statement An imaginary particle can decay in 0, 1 or 2 particles of the same kind with probabilities 1/4, 1/2 and 1/4, respectively. Beginning with one particle, we denote xi the number of particles in the ith generation. Determine: a. P(x2 >0) b. The probability that x1 = 2, given...